If you mean how to search each entry in the array to see if it contains a phrase or character then yes there is.
I realized after posting that I should've commented this out to explain what I'm doing.
//This declares the array of type string called arrayString and gives it 5 empty entries.
string[] arrayString(5);
//The following 5 lines store a string within the array in a unique entry.
arrayString[0]="Hi my name is George.";
arrayString[1]="Hi my name is Alex.";
arrayString[2]="Hi my name is Diana.";
arrayString[3]="Hi my name is Bobbie";
arrayString[4]="Hi my name is Lewis";
//This creates a loop through arrayString and checks each entry for the characters 'diana', I don't recall if the string_contains function is case sensitive or not. It then returns the string that contains the text. You can manipulate this easily enough to return the location of the character in the string as well as the entire string.
for(int x=0; x<arrayString.length; x++)
{
if(-1<string_contains(arrayString[x], "Diana", 1))
{
return arrayString[x];
}
}
Hope this helps!

Look at the help file in the bgt manual on string_contains.
Just change it to return string_contains(arrayString[x], "Diana");
That should return the position where the character set starts in the string.